3(1+d)+2=2(d+2)-4

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Solution for 3(1+d)+2=2(d+2)-4 equation: 



3(1+d)+2=2(d+2)-4

We move all terms to the left:

3(1+d)+2-(2(d+2)-4)=0

We add all the numbers together, and all the variables

3(d+1)-(2(d+2)-4)+2=0

We multiply parentheses

3d-(2(d+2)-4)+3+2=0



We calculate terms in parentheses: -(2(d+2)-4), so:

2(d+2)-4

We multiply parentheses

2d+4-4

We add all the numbers together, and all the variables

2d

Back to the equation:

-(2d)



We add all the numbers together, and all the variables

d+5=0

We move all terms containing d to the left, all other terms to the right

d=-5

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