2/3k+7/3-2k+2/3=2/3k-6=

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Solution for 2/3k+7/3-2k+2/3=2/3k-6= equation: 



2/3k+7/3-2k+2/3=2/3k-6=

We move all terms to the left:

2/3k+7/3-2k+2/3-(2/3k-6)=0



Domain of the equation: 3k!=0

k!=0/3

k!=0

k∈R





Domain of the equation: 3k-6)!=0

k∈R



We add all the numbers together, and all the variables

-2k+2/3k-(2/3k-6)+7/3+2/3=0

We get rid of parentheses

-2k+2/3k-2/3k+6+7/3+2/3=0

We calculate fractions


-2k+6=0

We move all terms containing k to the left, all other terms to the right

-2k=-6

k=-6/-2

k=+3

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