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3(1+b)=-2-2(2b+1
We move all terms to the left:
3(1+b)-(-2-2(2b+1)=0
We add all the numbers together, and all the variables
3(b+1)-(-2-2(2b+1)=0
We multiply parentheses
3b-(-2-2(2b+1)+3=0
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