4(n-2)-n=-10+2n

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Solution for 4(n-2)-n=-10+2n equation: 



4(n-2)-n=-10+2n

We move all terms to the left:

4(n-2)-n-(-10+2n)=0

We add all the numbers together, and all the variables

4(n-2)-n-(2n-10)=0

We add all the numbers together, and all the variables

-1n+4(n-2)-(2n-10)=0

We multiply parentheses

-1n+4n-(2n-10)-8=0

We get rid of parentheses

-1n+4n-2n+10-8=0

We add all the numbers together, and all the variables

n+2=0

We move all terms containing n to the left, all other terms to the right

n=-2

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