3(1+2m)=1/2(8+20m)

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Solution for 3(1+2m)=1/2(8+20m) equation: 



3(1+2m)=1/2(8+20m)

We move all terms to the left:

3(1+2m)-(1/2(8+20m))=0



Domain of the equation: 2(8+20m))!=0

m∈R



We add all the numbers together, and all the variables

3(2m+1)-(1/2(20m+8))=0

We multiply parentheses

6m-(1/2(20m+8))+3=0

We multiply all the terms by the denominator


6m*2(20m+8))-(1+3*2(20m+8))=0

Wy multiply elements

12m^2(2+6m(2=0

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