3/2b+b+(b+45)+(26-90)+90=540

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Solution for 3/2b+b+(b+45)+(26-90)+90=540 equation:



3/2b+b+(b+45)+(26-90)+90=540
We move all terms to the left:
3/2b+b+(b+45)+(26-90)+90-(540)=0
Domain of the equation: 2b!=0
b!=0/2
b!=0
b∈R
determiningTheFunctionDomain 3/2b+b+(b+45)+90-540+(26-90)=0
We add all the numbers together, and all the variables
3/2b+b+(b+45)+90-540+(-64)=0
We add all the numbers together, and all the variables
b+3/2b+(b+45)-514=0
We get rid of parentheses
b+3/2b+b+45-514=0
We multiply all the terms by the denominator
b*2b+b*2b+45*2b-514*2b+3=0
Wy multiply elements
2b^2+2b^2+90b-1028b+3=0
We add all the numbers together, and all the variables
4b^2-938b+3=0
a = 4; b = -938; c = +3;
Δ = b2-4ac
Δ = -9382-4·4·3
Δ = 879796
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{879796}=\sqrt{4*219949}=\sqrt{4}*\sqrt{219949}=2\sqrt{219949}$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-938)-2\sqrt{219949}}{2*4}=\frac{938-2\sqrt{219949}}{8} $
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-938)+2\sqrt{219949}}{2*4}=\frac{938+2\sqrt{219949}}{8} $

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