3(-k+5)=2(k+10)

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Solution for 3(-k+5)=2(k+10) equation: 



3(-k+5)=2(k+10)

We move all terms to the left:

3(-k+5)-(2(k+10))=0

We add all the numbers together, and all the variables

3(-1k+5)-(2(k+10))=0

We multiply parentheses

-3k-(2(k+10))+15=0



We calculate terms in parentheses: -(2(k+10)), so:

2(k+10)

We multiply parentheses

2k+20

Back to the equation:

-(2k+20)



We get rid of parentheses

-3k-2k-20+15=0

We add all the numbers together, and all the variables

-5k-5=0

We move all terms containing k to the left, all other terms to the right

-5k=5

k=5/-5

k=-1

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