1/5(y+3)=7

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Solution for 1/5(y+3)=7 equation: 



1/5(y+3)=7

We move all terms to the left:

1/5(y+3)-(7)=0



Domain of the equation: 5(y+3)!=0

y∈R



We multiply all the terms by the denominator


-7*5(y+3)+1=0

Wy multiply elements

-35y(y+1=0

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