3(-8y-1)+7=-6(4y+5)+34

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Solution for 3(-8y-1)+7=-6(4y+5)+34 equation: 



3(-8y-1)+7=-6(4y+5)+34

We move all terms to the left:

3(-8y-1)+7-(-6(4y+5)+34)=0

We multiply parentheses

-24y-(-6(4y+5)+34)-3+7=0



We calculate terms in parentheses: -(-6(4y+5)+34), so:

-6(4y+5)+34

We multiply parentheses

-24y-30+34

We add all the numbers together, and all the variables

-24y+4

Back to the equation:

-(-24y+4)



We add all the numbers together, and all the variables

-24y-(-24y+4)+4=0

We get rid of parentheses

-24y+24y-4+4=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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