5m-3(m-1/2)=-(3/2+2m)

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Solution for 5m-3(m-1/2)=-(3/2+2m) equation: 



5m-3(m-1/2)=-(3/2+2m)

We move all terms to the left:

5m-3(m-1/2)-(-(3/2+2m))=0



Domain of the equation: 2+2m))!=0

We move all terms containing m to the left, all other terms to the right

2m))!=-2

m!=-2/1

m!=-2

m∈R



We add all the numbers together, and all the variables

5m-3(+m-1/2)-(-(+2m+3/2))=0

We multiply parentheses

5m-3m-(-(+2m+3/2))+1/2*3=0

We calculate fractions


5m-3m+(-(-(+2m+3*2*3)/()+()/()=0



We calculate terms in parentheses: +(-(-(+2m+3*2*3)/()+()/(), so:

-(-(+2m+3*2*3)/()+()/(

We can not solve this equation

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