3(-4+4b)=-2(b-1)

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Solution for 3(-4+4b)=-2(b-1) equation: 



3(-4+4b)=-2(b-1)

We move all terms to the left:

3(-4+4b)-(-2(b-1))=0

We add all the numbers together, and all the variables

3(4b-4)-(-2(b-1))=0

We multiply parentheses

12b-(-2(b-1))-12=0



We calculate terms in parentheses: -(-2(b-1)), so:

-2(b-1)

We multiply parentheses

-2b+2

Back to the equation:

-(-2b+2)



We get rid of parentheses

12b+2b-2-12=0

We add all the numbers together, and all the variables

14b-14=0

We move all terms containing b to the left, all other terms to the right

14b=14

b=14/14

b=1

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