3(-3y+4)=18+2y

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Solution for 3(-3y+4)=18+2y equation: 



3(-3y+4)=18+2y

We move all terms to the left:

3(-3y+4)-(18+2y)=0

We add all the numbers together, and all the variables

3(-3y+4)-(2y+18)=0

We multiply parentheses

-9y-(2y+18)+12=0

We get rid of parentheses

-9y-2y-18+12=0

We add all the numbers together, and all the variables

-11y-6=0

We move all terms containing y to the left, all other terms to the right

-11y=6

y=6/-11

y=-6/11

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