-1/2(-10x+4)-7=3x+8(2x+1)

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Solution for -1/2(-10x+4)-7=3x+8(2x+1) equation: 



-1/2(-10x+4)-7=3x+8(2x+1)

We move all terms to the left:

-1/2(-10x+4)-7-(3x+8(2x+1))=0



Domain of the equation: 2(-10x+4)!=0

x∈R



We multiply all the terms by the denominator


-((3x+8(2x+1)))*2(-10x+4)-7*2(-10x+4)-1=0



We calculate terms in parentheses: -((3x+8(2x+1)))*2(-10x+4), so:

(3x+8(2x+1)))*2(-10x+4

We add all the numbers together, and all the variables

-10x+(3x+8(2x+1)))*2(+4

Back to the equation:

-(-10x+(3x+8(2x+1)))*2(+4)



We add all the numbers together, and all the variables

-(-10x+(3x+8(2x+1)))*24-7*2(-10x+4)-1=0

Wy multiply elements

-(-10x+(3x+8(2x+1)))*24-14x(--1=0

We use the square of the difference formula

-(-10x+(3x+8(2x+1)))*24-14x(+1=0

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