3(-2+4y)=40y-10

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Solution for 3(-2+4y)=40y-10 equation: 



3(-2+4y)=40y-10

We move all terms to the left:

3(-2+4y)-(40y-10)=0

We add all the numbers together, and all the variables

3(4y-2)-(40y-10)=0

We multiply parentheses

12y-(40y-10)-6=0

We get rid of parentheses

12y-40y+10-6=0

We add all the numbers together, and all the variables

-28y+4=0

We move all terms containing y to the left, all other terms to the right

-28y=-4

y=-4/-28

y=1/7

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