7(3x+12)+12x-16=33x+68

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Solution for 7(3x+12)+12x-16=33x+68 equation: 



7(3x+12)+12x-16=33x+68

We move all terms to the left:

7(3x+12)+12x-16-(33x+68)=0

We add all the numbers together, and all the variables

12x+7(3x+12)-(33x+68)-16=0

We multiply parentheses

12x+21x-(33x+68)+84-16=0

We get rid of parentheses

12x+21x-33x-68+84-16=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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