3(-+f)2=412

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Solution for 3(-+f)2=412 equation: 



3(-+f)2=412

We move all terms to the left:

3(-+f)2-(412)=0

We add all the numbers together, and all the variables

3(+f)2-412=0

We multiply parentheses

6f-412=0

We move all terms containing f to the left, all other terms to the right

6f=412

f=412/6

f=68+2/3

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