4(f+3)+4(f-1)=20

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Solution for 4(f+3)+4(f-1)=20 equation: 



4(f+3)+4(f-1)=20

We move all terms to the left:

4(f+3)+4(f-1)-(20)=0

We multiply parentheses

4f+4f+12-4-20=0

We add all the numbers together, and all the variables

8f-12=0

We move all terms containing f to the left, all other terms to the right

8f=12

f=12/8

f=1+1/2

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