If it's not what You are looking for type in the equation solver your own equation and let us solve it.
2z^2+20=0
a = 2; b = 0; c = +20;
Δ = b2-4ac
Δ = 02-4·2·20
Δ = -160
Delta is less than zero, so there is no solution for the equation
| 1/2(4x+6)=1/4(8x-8) | | 2/3a=-7 | | 2.25(4x-4)=(-2+10x+12) | | 3y+12=6y-33 | | 7+10x=40 | | x+4-3x=-20 | | 18.72-18r=-19.6r | | 5v-2=6v-17 | | 18x-4(4+2x)=10x-6 | | 30÷x=123/5 | | -7p=-4p+9 | | 4p+12=7p-27 | | 34=–0.4(p+22) | | 6z-4z=16 | | 9a−6a=18 | | I(8-3i)(8+3i)=0 | | 3^x-5=9^x+4 | | x+.04x=178 | | 9x+36=12x+24 | | 20n−16n=16 | | 19g-20g-8=16-3g | | 9/10=y+3/50 | | x-6+x-6+x=180 | | 7z-6z=17 | | 6q=8q+2 | | 35x-13=−103 | | 5s-4s=9 | | 5m+15=9m-53 | | -c/12=-3/4 | | 15+6=3(5y+2) | | 10n-9n=10 | | (10+8)x=66 |