3y+12=6y-33

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Solution for 3y+12=6y-33 equation: 



3y+12=6y-33

We move all terms to the left:

3y+12-(6y-33)=0

We get rid of parentheses

3y-6y+33+12=0

We add all the numbers together, and all the variables

-3y+45=0

We move all terms containing y to the left, all other terms to the right

-3y=-45

y=-45/-3

y=+15

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