2z/7-5=36

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Solution for 2z/7-5=36 equation: 



2z/7-5=36

We move all terms to the left:

2z/7-5-(36)=0

We add all the numbers together, and all the variables

2z/7-41=0

We multiply all the terms by the denominator


2z-41*7=0

We add all the numbers together, and all the variables

2z-287=0

We move all terms containing z to the left, all other terms to the right

2z=287

z=287/2

z=143+1/2

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