2(h+2)-3(h-3)=h+7

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Solution for 2(h+2)-3(h-3)=h+7 equation: 



2(h+2)-3(h-3)=h+7

We move all terms to the left:

2(h+2)-3(h-3)-(h+7)=0

We multiply parentheses

2h-3h-(h+7)+4+9=0

We get rid of parentheses

2h-3h-h-7+4+9=0

We add all the numbers together, and all the variables

-2h+6=0

We move all terms containing h to the left, all other terms to the right

-2h=-6

h=-6/-2

h=+3

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