2z-2z+4=3z-48z

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Solution for 2z-2z+4=3z-48z equation: 



2z-2z+4=3z-48z

We move all terms to the left:

2z-2z+4-(3z-48z)=0

We add all the numbers together, and all the variables

2z-2z-(-45z)+4=0

We add all the numbers together, and all the variables

-(-45z)+4=0

We get rid of parentheses

45z+4=0

We move all terms containing z to the left, all other terms to the right

45z=-4

z=-4/45

z=-4/45

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