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2x-5=1+3(x-2)
We move all terms to the left:
2x-5-(1+3(x-2))=0
We calculate terms in parentheses: -(1+3(x-2)), so:We get rid of parentheses
1+3(x-2)
determiningTheFunctionDomain 3(x-2)+1
We multiply parentheses
3x-6+1
We add all the numbers together, and all the variables
3x-5
Back to the equation:
-(3x-5)
2x-3x+5-5=0
We add all the numbers together, and all the variables
-x=0
x=0/-1
x=0
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