If it's not what You are looking for type in the equation solver your own equation and let us solve it.
1*x^4-(8*x^2)+0*x^3+0*x-9 = 0
1*x^4+2*x^2+0*x^3+0*x-8 = 0
k-5 = 3/14
e^(x^2)
x^(x^2)
| X+-27=-12 | | -4=n/-9=8 | | X+(x+25)+(2x+15)=350 | | 47=10x-133 | | 36=X-40% | | (x-1)(x+1)+23=10x | | 2(3p)+4p=140 | | 176=h+(-219) | | 23=5n-2 | | Cot(4x)=1 | | 12y-3x=12 | | 3(2-0.9h)=(-1.3h-4) | | (5x-6)+(5x+9)= | | 2(3p)=140+4V | | x-40%=36 | | 6/11=83? | | 13x+49=180 | | 9=1+2.4ln(d+1) | | (10x-35)=(7x+10) | | 2(3p)+4=140 | | (X-1)(x+1)+23=0 | | 116d-(4-5d)=-67 | | x-40%=35,99 | | 7x-3=-3+8x | | 1/8×1/8 | | 1/8×1/18 | | k-5=3/14 | | (1-5q)=2(2.5q+8) | | (2+i)(1+3i)= | | 8x^3-6x^2-23x+6=0 | | 7x-5y=-12 | | 10x+23(x-5)=380 |