(2+i)(1+3i)=

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Solution for (2+i)(1+3i)= equation:


Simplifying
(2 + i)(1 + 3i) = 0

Multiply (2 + i) * (1 + 3i)
(2(1 + 3i) + i(1 + 3i)) = 0
((1 * 2 + 3i * 2) + i(1 + 3i)) = 0
((2 + 6i) + i(1 + 3i)) = 0
(2 + 6i + (1 * i + 3i * i)) = 0
(2 + 6i + (1i + 3i2)) = 0

Combine like terms: 6i + 1i = 7i
(2 + 7i + 3i2) = 0

Solving
2 + 7i + 3i2 = 0

Solving for variable 'i'.

Factor a trinomial.
(2 + i)(1 + 3i) = 0

Subproblem 1

Set the factor '(2 + i)' equal to zero and attempt to solve: Simplifying 2 + i = 0 Solving 2 + i = 0 Move all terms containing i to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + i = 0 + -2 Combine like terms: 2 + -2 = 0 0 + i = 0 + -2 i = 0 + -2 Combine like terms: 0 + -2 = -2 i = -2 Simplifying i = -2

Subproblem 2

Set the factor '(1 + 3i)' equal to zero and attempt to solve: Simplifying 1 + 3i = 0 Solving 1 + 3i = 0 Move all terms containing i to the left, all other terms to the right. Add '-1' to each side of the equation. 1 + -1 + 3i = 0 + -1 Combine like terms: 1 + -1 = 0 0 + 3i = 0 + -1 3i = 0 + -1 Combine like terms: 0 + -1 = -1 3i = -1 Divide each side by '3'. i = -0.3333333333 Simplifying i = -0.3333333333

Solution

i = {-2, -0.3333333333}

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