2z+3/3+3z-4/6=z-2/2

Solution for 2z+3/3+3z-4/6=z-2/2 equation:

2z+3/3+3z-4/6=z-2/2

We move all terms to the left:

2z+3/3+3z-4/6-(z-2/2)=0

We add all the numbers together, and all the variables

2z+3z-(z-1)+3/3-4/6=0

We add all the numbers together, and all the variables

5z-(z-1)+1-4/6=0

We get rid of parentheses

5z-z+1+1-4/6=0

We multiply all the terms by the denominator


5z*6-z*6-4+1*6+1*6=0

We add all the numbers together, and all the variables

5z*6-z*6+8=0

Wy multiply elements

30z-6z+8=0

We add all the numbers together, and all the variables

24z+8=0

We move all terms containing z to the left, all other terms to the right

24z=-8

z=-8/24

z=-1/3