2z+12=7z-36

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Solution for 2z+12=7z-36 equation: 



2z+12=7z-36

We move all terms to the left:

2z+12-(7z-36)=0

We get rid of parentheses

2z-7z+36+12=0

We add all the numbers together, and all the variables

-5z+48=0

We move all terms containing z to the left, all other terms to the right

-5z=-48

z=-48/-5

z=9+3/5

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