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1/2(2g+4)=-6g-40
We move all terms to the left:
1/2(2g+4)-(-6g-40)=0
Domain of the equation: 2(2g+4)!=0We get rid of parentheses
g∈R
1/2(2g+4)+6g+40=0
We multiply all the terms by the denominator
6g*2(2g+4)+40*2(2g+4)+1=0
Wy multiply elements
12g^2(2+80g(2+1=0
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