2z(1.2+z)=2.4

Solution for 2z(1.2+z)=2.4 equation:

2z(1.2+z)=2.4

We move all terms to the left:

2z(1.2+z)-(2.4)=0

We add all the numbers together, and all the variables

2z(z+1.2)-(2.4)=0

We add all the numbers together, and all the variables

2z(z+1.2)-2.4=0

We multiply parentheses

2z^2+2.4z-2.4=0

a = 2; b = 2.4; c = -2.4;
Δ = b2-4ac
Δ = 2.42-4·2·(-2.4)
Δ = 24.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{24.96}}{2*2}=\frac{-2.4-\sqrt{24.96}}{4}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{24.96}}{2*2}=\frac{-2.4+\sqrt{24.96}}{4}
$