2y/6y-5y+3*4-4=0

Solution for 2y/6y-5y+3*4-4=0 equation:

2y/6y-5y+3*4-4=0


Domain of the equation: 6y!=0

y!=0/6

y!=0

y∈R


We add all the numbers together, and all the variables

-5y+2y/6y+8=0

We multiply all the terms by the denominator


-5y*6y+2y+8*6y=0

We add all the numbers together, and all the variables

2y-5y*6y+8*6y=0

Wy multiply elements

-30y^2+2y+48y=0

We add all the numbers together, and all the variables

-30y^2+50y=0

a = -30; b = 50; c = 0;
Δ = b2-4ac
Δ = 502-4·(-30)·0
Δ = 2500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2500}=50$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(50)-50}{2*-30}=\frac{-100}{-60}
=1+2/3
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(50)+50}{2*-30}=\frac{0}{-60}
=0
$