2y/2y+6+5y-6/3y+9=y-7/y-3

Solution for 2y/2y+6+5y-6/3y+9=y-7/y-3 equation:

2y/2y+6+5y-6/3y+9=y-7/y-3

We move all terms to the left:

2y/2y+6+5y-6/3y+9-(y-7/y-3)=0


Domain of the equation: 2y!=0

y!=0/2

y!=0

y∈R



Domain of the equation: 3y!=0

y!=0/3

y!=0

y∈R



Domain of the equation: y-3)!=0

y∈R


We add all the numbers together, and all the variables

5y+2y/2y-6/3y-(y-7/y-3)+15=0

We get rid of parentheses

5y+2y/2y-6/3y-y+7/y+3+15=0

Fractions to decimals

-6/3y+7/y+5y-y+3+15+1=0

We calculate fractions


5y-y+(-6y)/3y^2+21y/3y^2+3+15+1=0

We add all the numbers together, and all the variables

4y+(-6y)/3y^2+21y/3y^2+19=0

We multiply all the terms by the denominator


4y*3y^2+(-6y)+21y+19*3y^2=0

We add all the numbers together, and all the variables

21y+4y*3y^2+(-6y)+19*3y^2=0

Wy multiply elements

12y^3+57y^2+21y+(-6y)=0

We get rid of parentheses

12y^3+57y^2+21y-6y=0

We do not support eypression: y^3