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2=3x-9/4x-6
We move all terms to the left:
2-(3x-9/4x-6)=0
Domain of the equation: 4x-6)!=0We get rid of parentheses
x∈R
-3x+9/4x+6+2=0
We multiply all the terms by the denominator
-3x*4x+6*4x+2*4x+9=0
Wy multiply elements
-12x^2+24x+8x+9=0
We add all the numbers together, and all the variables
-12x^2+32x+9=0
a = -12; b = 32; c = +9;
Δ = b2-4ac
Δ = 322-4·(-12)·9
Δ = 1456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1456}=\sqrt{16*91}=\sqrt{16}*\sqrt{91}=4\sqrt{91}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-4\sqrt{91}}{2*-12}=\frac{-32-4\sqrt{91}}{-24} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+4\sqrt{91}}{2*-12}=\frac{-32+4\sqrt{91}}{-24} $
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