2y-5=5+8(y-4)

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Solution for 2y-5=5+8(y-4) equation: 



2y-5=5+8(y-4)

We move all terms to the left:

2y-5-(5+8(y-4))=0



We calculate terms in parentheses: -(5+8(y-4)), so:

5+8(y-4)

determiningTheFunctionDomain
8(y-4)+5

We multiply parentheses

8y-32+5

We add all the numbers together, and all the variables

8y-27

Back to the equation:

-(8y-27)



We get rid of parentheses

2y-8y+27-5=0

We add all the numbers together, and all the variables

-6y+22=0

We move all terms containing y to the left, all other terms to the right

-6y=-22

y=-22/-6

y=3+2/3

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