7(2z+1)=4(z-5)

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Solution for 7(2z+1)=4(z-5) equation: 



7(2z+1)=4(z-5)

We move all terms to the left:

7(2z+1)-(4(z-5))=0

We multiply parentheses

14z-(4(z-5))+7=0



We calculate terms in parentheses: -(4(z-5)), so:

4(z-5)

We multiply parentheses

4z-20

Back to the equation:

-(4z-20)



We get rid of parentheses

14z-4z+20+7=0

We add all the numbers together, and all the variables

10z+27=0

We move all terms containing z to the left, all other terms to the right

10z=-27

z=-27/10

z=-2+7/10

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