2y-5+3(3y+2)=-3(y+2)

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Solution for 2y-5+3(3y+2)=-3(y+2) equation: 



2y-5+3(3y+2)=-3(y+2)

We move all terms to the left:

2y-5+3(3y+2)-(-3(y+2))=0

We multiply parentheses

2y+9y-(-3(y+2))+6-5=0



We calculate terms in parentheses: -(-3(y+2)), so:

-3(y+2)

We multiply parentheses

-3y-6

Back to the equation:

-(-3y-6)



We add all the numbers together, and all the variables

11y-(-3y-6)+1=0

We get rid of parentheses

11y+3y+6+1=0

We add all the numbers together, and all the variables

14y+7=0

We move all terms containing y to the left, all other terms to the right

14y=-7

y=-7/14

y=-1/2

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