(-6y+(-12))/3=2(12-6)

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Solution for (-6y+(-12))/3=2(12-6) equation: 



(-6y+(-12))/3=2(12-6)

We move all terms to the left:

(-6y+(-12))/3-(2(12-6))=0

We add all the numbers together, and all the variables

(-6y+(-12))/3-(26)=0

We add all the numbers together, and all the variables

(-6y+(-12))/3-26=0

We multiply all the terms by the denominator


(-6y+(-12))-26*3=0



We calculate terms in parentheses: +(-6y+(-12)), so:

-6y+(-12)

We add all the numbers together, and all the variables

-6y-12

Back to the equation:

+(-6y-12)



We add all the numbers together, and all the variables

(-6y-12)-78=0

We get rid of parentheses

-6y-12-78=0

We add all the numbers together, and all the variables

-6y-90=0

We move all terms containing y to the left, all other terms to the right

-6y=90

y=90/-6

y=-15

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