2y-5(4y+5)=4-4(-3-y)

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Solution for 2y-5(4y+5)=4-4(-3-y) equation: 



2y-5(4y+5)=4-4(-3-y)

We move all terms to the left:

2y-5(4y+5)-(4-4(-3-y))=0

We add all the numbers together, and all the variables

2y-5(4y+5)-(4-4(-1y-3))=0

We multiply parentheses

2y-20y-(4-4(-1y-3))-25=0



We calculate terms in parentheses: -(4-4(-1y-3)), so:

4-4(-1y-3)

determiningTheFunctionDomain
-4(-1y-3)+4

We multiply parentheses

4y+12+4

We add all the numbers together, and all the variables

4y+16

Back to the equation:

-(4y+16)



We add all the numbers together, and all the variables

-18y-(4y+16)-25=0

We get rid of parentheses

-18y-4y-16-25=0

We add all the numbers together, and all the variables

-22y-41=0

We move all terms containing y to the left, all other terms to the right

-22y=41

y=41/-22

y=-1+19/22

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