2y-4=2(6y+6)

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Solution for 2y-4=2(6y+6) equation: 



2y-4=2(6y+6)

We move all terms to the left:

2y-4-(2(6y+6))=0



We calculate terms in parentheses: -(2(6y+6)), so:

2(6y+6)

We multiply parentheses

12y+12

Back to the equation:

-(12y+12)



We get rid of parentheses

2y-12y-12-4=0

We add all the numbers together, and all the variables

-10y-16=0

We move all terms containing y to the left, all other terms to the right

-10y=16

y=16/-10

y=-1+3/5

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