2y-4=3(6y+7)

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Solution for 2y-4=3(6y+7) equation: 



2y-4=3(6y+7)

We move all terms to the left:

2y-4-(3(6y+7))=0



We calculate terms in parentheses: -(3(6y+7)), so:

3(6y+7)

We multiply parentheses

18y+21

Back to the equation:

-(18y+21)



We get rid of parentheses

2y-18y-21-4=0

We add all the numbers together, and all the variables

-16y-25=0

We move all terms containing y to the left, all other terms to the right

-16y=25

y=25/-16

y=-1+9/16

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