2y-3(y-1)=8-2(y-)

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Solution for 2y-3(y-1)=8-2(y-) equation: 



2y-3(y-1)=8-2(y-)

We move all terms to the left:

2y-3(y-1)-(8-2(y-))=0

We add all the numbers together, and all the variables

2y-3(y-1)-(8-2(+y))=0

We multiply parentheses

2y-3y-(8-2(+y))+3=0



We calculate terms in parentheses: -(8-2(+y)), so:

8-2(+y)

determiningTheFunctionDomain
-2(+y)+8

We multiply parentheses

-2y+8

Back to the equation:

-(-2y+8)



We add all the numbers together, and all the variables

-1y-(-2y+8)+3=0

We get rid of parentheses

-1y+2y-8+3=0

We add all the numbers together, and all the variables

y-5=0

We move all terms containing y to the left, all other terms to the right

y=5

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