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6(y-3)=4(3y-5)
We move all terms to the left:
6(y-3)-(4(3y-5))=0
We multiply parentheses
6y-(4(3y-5))-18=0
We calculate terms in parentheses: -(4(3y-5)), so:We get rid of parentheses
4(3y-5)
We multiply parentheses
12y-20
Back to the equation:
-(12y-20)
6y-12y+20-18=0
We add all the numbers together, and all the variables
-6y+2=0
We move all terms containing y to the left, all other terms to the right
-6y=-2
y=-2/-6
y=1/3
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