2y-10=-6(y+3)

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Solution for 2y-10=-6(y+3) equation: 



2y-10=-6(y+3)

We move all terms to the left:

2y-10-(-6(y+3))=0



We calculate terms in parentheses: -(-6(y+3)), so:

-6(y+3)

We multiply parentheses

-6y-18

Back to the equation:

-(-6y-18)



We get rid of parentheses

2y+6y+18-10=0

We add all the numbers together, and all the variables

8y+8=0

We move all terms containing y to the left, all other terms to the right

8y=-8

y=-8/8

y=-1

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