8(y+8)-2(y-4)=3(y-5)

Solution for 8(y+8)-2(y-4)=3(y-5) equation:

8(y+8)-2(y-4)=3(y-5)

We move all terms to the left:

8(y+8)-2(y-4)-(3(y-5))=0

We multiply parentheses

8y-2y-(3(y-5))+64+8=0


We calculate terms in parentheses: -(3(y-5)), so:

3(y-5)

We multiply parentheses

3y-15

Back to the equation:

-(3y-15)


We add all the numbers together, and all the variables

6y-(3y-15)+72=0

We get rid of parentheses

6y-3y+15+72=0

We add all the numbers together, and all the variables

3y+87=0

We move all terms containing y to the left, all other terms to the right

3y=-87

y=-87/3

y=-29