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2y-(15-8y)=5(2y-3)
We move all terms to the left:
2y-(15-8y)-(5(2y-3))=0
We add all the numbers together, and all the variables
2y-(-8y+15)-(5(2y-3))=0
We get rid of parentheses
2y+8y-(5(2y-3))-15=0
We calculate terms in parentheses: -(5(2y-3)), so:We add all the numbers together, and all the variables
5(2y-3)
We multiply parentheses
10y-15
Back to the equation:
-(10y-15)
10y-(10y-15)-15=0
We get rid of parentheses
10y-10y+15-15=0
We add all the numbers together, and all the variables
=0
y=0/1
y=0
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