-2(4v-3)+7v=9+2(7v-6)

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Solution for -2(4v-3)+7v=9+2(7v-6) equation: 



-2(4v-3)+7v=9+2(7v-6)

We move all terms to the left:

-2(4v-3)+7v-(9+2(7v-6))=0

We add all the numbers together, and all the variables

7v-2(4v-3)-(9+2(7v-6))=0

We multiply parentheses

7v-8v-(9+2(7v-6))+6=0



We calculate terms in parentheses: -(9+2(7v-6)), so:

9+2(7v-6)

determiningTheFunctionDomain
2(7v-6)+9

We multiply parentheses

14v-12+9

We add all the numbers together, and all the variables

14v-3

Back to the equation:

-(14v-3)



We add all the numbers together, and all the variables

-1v-(14v-3)+6=0

We get rid of parentheses

-1v-14v+3+6=0

We add all the numbers together, and all the variables

-15v+9=0

We move all terms containing v to the left, all other terms to the right

-15v=-9

v=-9/-15

v=3/5

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