2y+6(4y-16)=18

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Solution for 2y+6(4y-16)=18 equation: 



2y+6(4y-16)=18

We move all terms to the left:

2y+6(4y-16)-(18)=0

We multiply parentheses

2y+24y-96-18=0

We add all the numbers together, and all the variables

26y-114=0

We move all terms containing y to the left, all other terms to the right

26y=114

y=114/26

y=4+5/13

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