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4(x-4)+9=2x+2(-5+x)
We move all terms to the left:
4(x-4)+9-(2x+2(-5+x))=0
We add all the numbers together, and all the variables
4(x-4)-(2x+2(x-5))+9=0
We multiply parentheses
4x-(2x+2(x-5))-16+9=0
We calculate terms in parentheses: -(2x+2(x-5)), so:We add all the numbers together, and all the variables
2x+2(x-5)
We multiply parentheses
2x+2x-10
We add all the numbers together, and all the variables
4x-10
Back to the equation:
-(4x-10)
4x-(4x-10)-7=0
We get rid of parentheses
4x-4x+10-7=0
We add all the numbers together, and all the variables
3!=0
There is no solution for this equation
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