2y+4y+6y=-36(y+5)

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Solution for 2y+4y+6y=-36(y+5) equation: 



2y+4y+6y=-36(y+5)

We move all terms to the left:

2y+4y+6y-(-36(y+5))=0

We add all the numbers together, and all the variables

12y-(-36(y+5))=0



We calculate terms in parentheses: -(-36(y+5)), so:

-36(y+5)

We multiply parentheses

-36y-180

Back to the equation:

-(-36y-180)



We get rid of parentheses

12y+36y+180=0

We add all the numbers together, and all the variables

48y+180=0

We move all terms containing y to the left, all other terms to the right

48y=-180

y=-180/48

y=-3+3/4

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