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16x^2=30
We move all terms to the left:
16x^2-(30)=0
a = 16; b = 0; c = -30;
Δ = b2-4ac
Δ = 02-4·16·(-30)
Δ = 1920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1920}=\sqrt{64*30}=\sqrt{64}*\sqrt{30}=8\sqrt{30}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-8\sqrt{30}}{2*16}=\frac{0-8\sqrt{30}}{32} =-\frac{8\sqrt{30}}{32} =-\frac{\sqrt{30}}{4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+8\sqrt{30}}{2*16}=\frac{0+8\sqrt{30}}{32} =\frac{8\sqrt{30}}{32} =\frac{\sqrt{30}}{4} $
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