2y+42=-6(y-3)

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Solution for 2y+42=-6(y-3) equation: 



2y+42=-6(y-3)

We move all terms to the left:

2y+42-(-6(y-3))=0



We calculate terms in parentheses: -(-6(y-3)), so:

-6(y-3)

We multiply parentheses

-6y+18

Back to the equation:

-(-6y+18)



We get rid of parentheses

2y+6y-18+42=0

We add all the numbers together, and all the variables

8y+24=0

We move all terms containing y to the left, all other terms to the right

8y=-24

y=-24/8

y=-3

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